Ratios Of Complementary Angles - ConceptEra

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Ratios of Complementary Angles

Q- If sin 17°= x/y, let us show that–sec17°-sin73°=x²/y√y²-x²

Chapter: Ratios of Complementary Angles

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Q- If two angles α and β are complementary angles, let us show that–(i)sin²α+sin²β=1 (ii)cotβ+cosβ=(cosβ/cosα)(1+sinβ) (iii)(secα/cosα)-cot²β=1

Chapter: Ratios of Complementary Angles

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Q- Let us show that–(i)cosec²48°-tan²42°=1 (ii)sec70°sin20°+cos20°cosec70°=2

Chapter: Ratios of Complementary Angles

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Q- Let us show that–(i)sin66°-cos24°=0 (ii)cos²57°+cos²33°=1 (iii)cos²75°-sin²15°

Chapter: Ratios of Complementary Angles

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Q- Let us evaluate–(i)(sin38°/cos52°) (ii)(cosec79°/sec11°) (iii)(tan27°/cot63°)

Chapter: Ratios of Complementary Angles

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Q- ∠A + ∠B =90°, let us show that–1+(tanA/tanB)=sec²A

Chapter: Ratios of Complementary Angles

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Q- let us show that–sec²12°-(1/tan²78°)=1

Chapter: Ratios of Complementary Angles

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Q- let us prove that–cot12°cot38°cot52°cot78°cot 60°=1/√3

Chapter: Ratios of Complementary Angles

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Q- If ∠P + ∠Q = 90°– let us show that–√(sinP/cosQ)-sinPcosQ=cosP

Chapter: Ratios of Complementary Angles

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Q- let us show that–cosec²22°cot²68°=sin²22°+sin²68°+cot²68°

Chapter: Ratios of Complementary Angles

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